|
NO |
Soal |
Penyelesaian |
|
||||
|
1. |
192.168.1.60/24 |
2(32-24) = 28 = 256 Net ID = 192.168.1.0 Broadcast = 192.168.1.255 Host ID = 192.168.1.1 – 254 |
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||||
|
2. |
192.168.1.30/25 |
2(32-25) = 27 =
128 Net
ID = 192.168.1.0 Broadcast
= 192.168.1.127 Host
ID = 192.168.1.1-126 Subnet
Mask = 255.255.255.255-128 = 255.255.255.127 |
|
||||
|
3. |
192.168.1.24/26 |
2(32-26)
= 26 = 64 Net ID = 192.168.1.0 Broadcast = 192.168.1.63 Host ID = 192.168.1.1 – 62 Subnet Mask = 255.255.255.255 – 64 = 255.255.255.191 |
|
||||
|
4. |
193.168.1.38/27 |
2(32-27) = 25
= 32 Net
ID = 193.168.1.0 Broadcast
= 193.168.1.31 Host
ID = 193.168.1.1 – 30 Subnet
Mask = 255.255.255.255 – 32 = 255.255.255.223 |
|
||||
|
4.a |
|
2(32-27)
= 25 = 32 Net ID = 193.168.1.0 Broadcast = 193.168.1.31 Host ID = 193.168.1.33 – 62 Subnet Mask =
255.255.255.255 – 32 = 255.255.255.223 |
|
||||
|
5. |
193.168.1.28/28 |
2(32-28) = 24 =
16 Net
ID = 193.168.1.0 Broadcast
= 193.168.1.15 Host
ID = 193.168.1.1 – 14 Subnet
Mask = 255.255.255.255 – 16 = 255.255.255.239 |
|
||||
|
5.a |
|
2(32-28)
= 24 = 16 Net ID = 193.168.1.0 Broadcast = 193.168.1.15 Host ID = 193.168.1.17 – 30 Subnet Mask = 255.255.255.255 – 16 = 255.255.255.239 |
|
||||
|
6. |
199.169.9.29/29 |
2(32-29) = 23 = 8 Net
ID = 199. 169.1.0 Broadcast
= 199.169.1.7 Host
ID = 199.169.1.1 – 6 Subnet
Mask = 255.255.255.255 – 8 = 255.255.255.247 |
|
||||
|
6.a |
|
2(32-29)
= 23 = 8 Net ID = 199.169.1.0 Broadcast = 199.169.1.7 Host ID = 199.169.1.9 - 14 Subnet Mask = 255.255.255.255 – 8 |
|
||||
|
6.b |
|
2(32-29) = 23 = 8 Net
ID = 199.169.1.0 Broadcast
= 199.169.1.7 Host
ID = 199.169.1.17 - 22 Subnet
Mask = 255.255.255.255 – 8 = 255.255.255.247 |
|
||||
|
6.c |
|
2(32-29)
= 23 = 8 Net ID = 199.169.1.0 Broadcast = 199.169.1.7 Host ID = 199.169.1.25 - 30 Subnet Mask = 255.255.255.255 – 8 = 255.255.255.247 |
|
||||
|
7. |
|
192.169.1.10/30 |
2(32-30) = 22
= 4 Net
ID = 192.169.1.0 Broadcast
= 192.169.1.3 Host
ID = 192.169.1.1 – 2 Subnet
Mask = 255.255.255.255 – 4 = 255.255.255.251 |
||||
|
7.a |
|
2(32-30)
= 22 = 4 Net ID = 192.169.1.0 Broadcast = 192.169.1.3 Host ID = 192.169.1.5 – 6 Subnet Mask = 255.255.255.255 – 4 = 255.255.255.251 |
|
||||
|
7.b |
|
2(32-30) = 22
= 4 Net
ID = 192.169.1.0 Broadcast
= 192.169.1.3 Host
ID = 192.169.1.9 – 10 Subnet
Mask = 255.255.255.255 – 4 = 255.255.255.251 |
|
||||
MAKALAH JARINGAN DASAR PENGKABELAN JARINGAN KOMPUTER Disusun oleh: · Chairul Aziz Armondya · Dzaky Haidar · Surya Rifqi Fadhilah Kata Pengantar Segala puji dan syukur mari kita panjatkan kepada Allah Yang Maha Esa karena berkat rahmat dan nikmatnya kami dapat menyelesaikan makalah ini. Shalawat beserta salam mari kita curahkan kepada nabi besar kita Nabi Muhammad SAW yang semoga sampai kepada para keluargnya, sahabatnya dan juga kita sebagai para umatnya. Beliau juga telah membawa kita dari zaman kegelapan hingga zaman terang benderang seperti saat ini, dan semoga kita semua bisa menjadi hamba yang baik dihadapan ALLAH SWT. Daftar isi 1. Kata Pengantar.........................................................ii 2. Daftar isi................................................
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